WebHow many terms of the A.P; 24,21,18,... must be taken such that their sum is 78 Easy Solution Verified by Toppr Formula, S n= 2n[2a+(n−1)d] Given, a=24,d=21−24=−3,S n=78 78= 2n[2(24)+(n−1)(−3)] 156=n[48−3n+3] 3n 2−51n+156=0 n 2−17n+52=0 (n−13)(n−4)=0 ∴n=4,13 Was this answer helpful? 0 0 Similar questions Web14 jan. 2024 · Best answer Solution: Given AP is -6, -11/2, -5… Here a = –6, d = (–11/2) + 6 = 1/2 Sum of n terms of AP, Sn = – 25 Using sum of n term of AP formula ⇒ n2 – 25n + 100 = 0 ⇒ n2 – 20n – 5n + 100 = 0 ⇒ n (n – 20) – 5 (n – 20) = 0 ⇒ (n – 20) (n – 5) = 0 ⇒ (n – 20) = 0 or (n – 5) = 0 ∴ n = 20 or n = 5 ← Prev Question Next Question →
How many terms of the AP 21, 18, 15 … must be added to get
Web13 okt. 2024 · Step-by-step explanation: The given AP is,27,24,21,.... Here first term= a=27 common difference=d=24-27=-3 Let the nth term of the AP=0 => a+ (n-1)d=0 =>27+ (n-1) (-3)=0 => (n-1)= (-27)/ (-3) => n-1=9 => n=9+1 => n=10 So, the 10th term of the AP is 0. hope it will help you. Advertisement dawin32arpit Answer: 10 please mark as brainlist answer Web8 feb. 2024 · answered Feb 8, 2024 by Beepin (59.2k points) selected Feb 9, 2024 by KumkumBharti Best answer In the given A.P; a = 24, d = 4, Sn = 72 we have Sn = n/2 {2a + (n – 1)d} 72 = n/2 {2 (24) + (n – 1) (-4)} = 144 = n {48 – 4n + 4} ⇒ 144 = n {52 – 4n} ⇒ 144 = 52n – 4n2 ⇒ 4n2 – 52n + 144 = 0 ⇒ n2 – 13n + 36 = 0 ⇒ (n – 9) (n – 4) = 0 ∴ n = 9, 4 how much people live in england
How many terms of an AP 27, 24, and 21 should be taken so that …
Web12 dec. 2016 · How many terms of the AP 27,24,21, should be taken so that their sum is zero - Maths - Arithmetic Progressions Web11 apr. 2024 · And the common difference (d) of the A.P is. ⇒ d = ( 21 − 24) = ( 18 − 21) = − 3. Now we have to find out the number of terms in the A.P if the sum of an A.P is 78. As … WebHow many terms of AP:27,24,21,..... should be taken so that their sum is zero? What is the value of that last term. how do i vector an image in photoshop